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x^2+14x+0.009=0
a = 1; b = 14; c = +0.009;
Δ = b2-4ac
Δ = 142-4·1·0.009
Δ = 195.964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-\sqrt{195.964}}{2*1}=\frac{-14-\sqrt{195.964}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+\sqrt{195.964}}{2*1}=\frac{-14+\sqrt{195.964}}{2} $
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